JEE Strategy Series · Geometric progression
You know the middle term in a list of numbers, but you do not know its multiplier. Can you still find the product of five terms? This worked sample shows why choosing what to calculate matters as much as knowing a formula.
I am Dr. Biplab Pal, the author of Develop Strategic Math Mind for JEE – Vol1. Try this complete example before deciding whether the book's approach suits you. You will need basic powers and multiplication.
1. The exact book question
“A GP has third term 4. Find the product of its first five terms.”
Source: Develop Strategic Math Mind for JEE – Vol1, Complete Edition, book problem E089, printed page 106; one-based PDF page 106 in the checked print interior. Kindle locations may differ. The book labels this IIT-JEE 1982. That is secondary book attribution: the original official paper wording and question number have not been independently verified. E089 is the book's identifier.
What does GP mean? A geometric progression is a list where you multiply by the same number at each step. For example, 2, 6, 18 uses a multiplier of 3. A product means the result of multiplying numbers together.
2. What do you need to find?
The third term is the middle of the first five terms. The question asks for their product, not the first term or the multiplier. It appears to test whether you can spot equal-distance pairs and use powers; that is a teaching interpretation of the question.
Pause and try: pair the first term with the fifth, and the second with the fourth. What might both pairs have in common with the middle term? Take a moment before reading on.
3. Pair the terms and solve
Call the first term a and the multiplier r. The five terms are:
a ar ar² ar³ ar⁴
The middle term is ar² = 4. Now multiply the pairs:
- First × fifth: a × ar⁴ = a²r⁴ = (ar²)² = 16.
- Second × fourth: ar × ar³ = a²r⁴ = (ar²)² = 16.
The middle 4 remains unpaired. Therefore the product of all five terms is 16 × 4 × 16 = 4⁵ = 1024.
A common trap: do not choose a convenient multiplier and treat it as given. A negative multiplier is allowed, too. Because the middle term is nonzero, neither the first term nor the multiplier can be zero.
Check: 1, −2, 4, −8, 16 has middle term 4. The outer pair gives 16, the inner pair gives 16, and the full product is again 1024. The unknown multiplier never needed to be found.
Try one small change
This is a separate, author-created teaching check: if the third term were 3 instead, what would the five-term product be?
Use the same pairs: 3² × 3 × 3² = 3⁵ = 243. For the original book question, the answer remains 1024.
Is this the kind of practice you need?
This sample is for students who want to understand why a method works and when to use it. If basic powers or the meaning of a sequence are still unfamiliar, practise those first. A worked-example book should support your learning and exam practice; it cannot promise a score or admission.
For more examples, my book Develop Strategic Math Mind for JEE – Vol1: 400 Past JEE Math Problems Analyzed Through Visual Strategies is available in English as a Kindle eBook. The listing covers algebra, trigonometry, counting, probability and statistics.
See the Kindle book and Read sample on Amazon India. Check the current price and your account's purchase options on Amazon. Preview the sample before deciding; the full book is a paid purchase. This is an author promotion for my own book.
